10 25 28 triangle

Obtuse scalene triangle.

Sides: a = 10   b = 25   c = 28

Area: T = 124.1276699384
Perimeter: p = 63
Semiperimeter: s = 31.5

Angle ∠ A = α = 20.77218550453° = 20°46'19″ = 0.36325372623 rad
Angle ∠ B = β = 62.45114540405° = 62°27'5″ = 1.09899834957 rad
Angle ∠ C = γ = 96.77766909142° = 96°46'36″ = 1.68990718956 rad

Height: ha = 24.82553398768
Height: hb = 9.93301359507
Height: hc = 8.86661928132

Median: ma = 26.06772207955
Median: mb = 16.90441415044
Median: mc = 12.90334879006

Vertex coordinates: A[28; 0] B[0; 0] C[4.625; 8.86661928132]
Centroid: CG[10.875; 2.95553976044]
Coordinates of the circumscribed circle: U[14; -1.66436227421]
Coordinates of the inscribed circle: I[6.5; 3.94105301392]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 159.2288144955° = 159°13'41″ = 0.36325372623 rad
∠ B' = β' = 117.5498545959° = 117°32'55″ = 1.09899834957 rad
∠ C' = γ' = 83.22333090858° = 83°13'24″ = 1.68990718956 rad

How did we calculate this triangle?

Now we know the lengths of all three sides of the triangle and the triangle is uniquely determined. Next we calculate another its characteristics - same procedure as calculation of the triangle from the known three sides SSS. 1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines    