1.2 1.2 0.9 triangle

Acute isosceles triangle.

Sides: a = 1.2   b = 1.2   c = 0.9

Area: T = 0.50105933979
Perimeter: p = 3.3
Semiperimeter: s = 1.65

Angle ∠ A = α = 67.9765687163° = 67°58'32″ = 1.18663995523 rad
Angle ∠ B = β = 67.9765687163° = 67°58'32″ = 1.18663995523 rad
Angle ∠ C = γ = 44.04986256741° = 44°2'55″ = 0.7698793549 rad

Height: ha = 0.83443223298
Height: hb = 0.83443223298
Height: hc = 1.11224297731

Median: ma = 0.87546427842
Median: mb = 0.87546427842
Median: mc = 1.11224297731

Inradius: r = 0.30333899381
Circumradius: R = 0.6477231868

Vertex coordinates: A[0.9; 0] B[0; 0] C[0.45; 1.11224297731]
Centroid: CG[0.45; 0.37108099244]
Coordinates of the circumscribed circle: U[0.45; 0.46551979051]
Coordinates of the inscribed circle: I[0.45; 0.30333899381]

Exterior(or external, outer) angles of the triangle:
∠ A' = α' = 112.0244312837° = 112°1'28″ = 1.18663995523 rad
∠ B' = β' = 112.0244312837° = 112°1'28″ = 1.18663995523 rad
∠ C' = γ' = 135.9511374326° = 135°57'5″ = 0.7698793549 rad

How did we calculate this triangle?

1. The triangle circumference is the sum of the lengths of its three sides 2. Semiperimeter of the triangle 3. The triangle area using Heron's formula 4. Calculate the heights of the triangle from its area. 5. Calculation of the inner angles of the triangle using a Law of Cosines     